The Theory of Electro Magnetic Force of Capacitor

Introduction: 

Electro magnetic force means a magnetic force around a charged particle. Every electrolytic capacitor has its own Electro magnetic force. In this article we will discuss about the Electro magnetic force of electrolytic capacitor.

Abstract:

When electric conduction starts in a electric device, there a strong magnetic force creates in that electric device. Here we will discuss about the magnetic force of capacitor. 

Method:  

I have invented a formula to determine the value of Electro magnetic force of electrolytic capacitor. Here’s the method-

We know that- B= k'QV÷r²

                          = k’QV÷C²k²

                          = N₀QV÷C²

So, B= N₀QV÷C²__________(i)

If QV= 2QV then-

B’= N₀×2QV÷C²

   = 2N₀QV÷C²

   = 2B

So, B'= 2B

If QV= ½QV then-

B'= N₀×½QV÷C²

   = ½N₀QV÷C²

  = ½B

So, B’= ½B

If the value of the charge and potential difference  of a electrolytic capacitor increases, then the value of the force of the electrolytic capacitor increases proportionally. If the square value of the charge and potential difference   of a electrolytic capacitor decreases, then the value of the force of the electrolytic capacitor decreases proportionally.

So, B∞ QV_________(ii)

If C=2C then- 

B'= N₀QV÷(2C)²

   = N₀QV÷4C²

   = ¼(N₀QV÷C²)

   = ¼B

So, B'= ¼B

Again, if C= ½C then-

B'= N₀QV÷(½C)²

   = N₀QV÷¼C²

   = 4(N₀QV÷C²)

   = 4B

So, B’= 4B

If the square value of capacitance increases, the value of the electro magnetic force of that object decreases. Again, the value of capacitance decreases, the value of electro magnetic force of that object increases. 

So, B∞ 1÷C²_________(iii)

The graph of equation of ii no.-

The graph of iii no. equation- 

From ii and iii number equation- 

B∞ QV_________(ii)

B∞ 1÷C²_________(iii)

So, B∞ QV×1÷C²

Or, B∞ QV÷C²

So, B= N₀QV÷C²

Here, N₀- is a proportional constant. 

Constant's Calculation:

Here, N₀- is a proportional constant. 

N₀= k'/k²

    = μ₀÷4π/1÷(4πε₀)²

    = μ₀÷4π×16π²ε₀²

    = 4πμ₀ε₀²

    = 4×3.1416×4×3.1416×10⁻⁷×(8.85×10⁻¹²)²  

    = 1.23682513×10⁻²⁷ Nm⁻⁴ A⁻² C⁴

The value of N₀ is 1.23682513×10⁻²⁷ Nm⁻⁴ A⁻² C⁴. For calculation we can use 1.237×10⁻²⁷ Nm⁻⁴ A⁻² C⁴

About Magnetic Force:

When the electricity supplies in whole circuit, then a magnetic force creates in whole circuit. The flowing electrons enter the capacitor by positive side of capacitor and out by the negative side of the capacitor. There creates a strong magnetic force in the capacitor. If the electricity supply become stop the magnetic force will be stop. The magnetic force depends on electricity. 

Result: 

The value of magnetic force of a capacitor is proportional to the value of charge and potential difference and disproportional to the square value of its capacitance. 

Conditions Of This Law:  

There are some conditions of this law. Here’s that-

i) This law is only for capacitor. 

ii) The position of capacitor should be in a circuit

Conclusion: 

If we know the value of capacitor’s charge, potential difference and capacitance. We can determine the value of capacitor’s magnetic force.